Optimal. Leaf size=151 \[ -\frac{2 b^{3/2} (A b-a B) \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{(b d-a e)^{7/2}}+\frac{2 b (A b-a B)}{\sqrt{d+e x} (b d-a e)^3}+\frac{2 (A b-a B)}{3 (d+e x)^{3/2} (b d-a e)^2}-\frac{2 (B d-A e)}{5 e (d+e x)^{5/2} (b d-a e)} \]
[Out]
________________________________________________________________________________________
Rubi [A] time = 0.0949952, antiderivative size = 151, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 4, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.182, Rules used = {78, 51, 63, 208} \[ -\frac{2 b^{3/2} (A b-a B) \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{(b d-a e)^{7/2}}+\frac{2 b (A b-a B)}{\sqrt{d+e x} (b d-a e)^3}+\frac{2 (A b-a B)}{3 (d+e x)^{3/2} (b d-a e)^2}-\frac{2 (B d-A e)}{5 e (d+e x)^{5/2} (b d-a e)} \]
Antiderivative was successfully verified.
[In]
[Out]
Rule 78
Rule 51
Rule 63
Rule 208
Rubi steps
\begin{align*} \int \frac{A+B x}{(a+b x) (d+e x)^{7/2}} \, dx &=-\frac{2 (B d-A e)}{5 e (b d-a e) (d+e x)^{5/2}}+\frac{(A b-a B) \int \frac{1}{(a+b x) (d+e x)^{5/2}} \, dx}{b d-a e}\\ &=-\frac{2 (B d-A e)}{5 e (b d-a e) (d+e x)^{5/2}}+\frac{2 (A b-a B)}{3 (b d-a e)^2 (d+e x)^{3/2}}+\frac{(b (A b-a B)) \int \frac{1}{(a+b x) (d+e x)^{3/2}} \, dx}{(b d-a e)^2}\\ &=-\frac{2 (B d-A e)}{5 e (b d-a e) (d+e x)^{5/2}}+\frac{2 (A b-a B)}{3 (b d-a e)^2 (d+e x)^{3/2}}+\frac{2 b (A b-a B)}{(b d-a e)^3 \sqrt{d+e x}}+\frac{\left (b^2 (A b-a B)\right ) \int \frac{1}{(a+b x) \sqrt{d+e x}} \, dx}{(b d-a e)^3}\\ &=-\frac{2 (B d-A e)}{5 e (b d-a e) (d+e x)^{5/2}}+\frac{2 (A b-a B)}{3 (b d-a e)^2 (d+e x)^{3/2}}+\frac{2 b (A b-a B)}{(b d-a e)^3 \sqrt{d+e x}}+\frac{\left (2 b^2 (A b-a B)\right ) \operatorname{Subst}\left (\int \frac{1}{a-\frac{b d}{e}+\frac{b x^2}{e}} \, dx,x,\sqrt{d+e x}\right )}{e (b d-a e)^3}\\ &=-\frac{2 (B d-A e)}{5 e (b d-a e) (d+e x)^{5/2}}+\frac{2 (A b-a B)}{3 (b d-a e)^2 (d+e x)^{3/2}}+\frac{2 b (A b-a B)}{(b d-a e)^3 \sqrt{d+e x}}-\frac{2 b^{3/2} (A b-a B) \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{(b d-a e)^{7/2}}\\ \end{align*}
Mathematica [C] time = 0.0390751, size = 86, normalized size = 0.57 \[ \frac{10 e (d+e x) (A b-a B) \, _2F_1\left (-\frac{3}{2},1;-\frac{1}{2};\frac{b (d+e x)}{b d-a e}\right )-6 (b d-a e) (B d-A e)}{15 e (d+e x)^{5/2} (b d-a e)^2} \]
Antiderivative was successfully verified.
[In]
[Out]
________________________________________________________________________________________
Maple [A] time = 0.015, size = 234, normalized size = 1.6 \begin{align*} -{\frac{2\,A}{5\,ae-5\,bd} \left ( ex+d \right ) ^{-{\frac{5}{2}}}}+{\frac{2\,Bd}{5\,e \left ( ae-bd \right ) } \left ( ex+d \right ) ^{-{\frac{5}{2}}}}-2\,{\frac{A{b}^{2}}{ \left ( ae-bd \right ) ^{3}\sqrt{ex+d}}}+2\,{\frac{Bba}{ \left ( ae-bd \right ) ^{3}\sqrt{ex+d}}}+{\frac{2\,Ab}{3\, \left ( ae-bd \right ) ^{2}} \left ( ex+d \right ) ^{-{\frac{3}{2}}}}-{\frac{2\,Ba}{3\, \left ( ae-bd \right ) ^{2}} \left ( ex+d \right ) ^{-{\frac{3}{2}}}}-2\,{\frac{{b}^{3}A}{ \left ( ae-bd \right ) ^{3}\sqrt{ \left ( ae-bd \right ) b}}\arctan \left ({\frac{b\sqrt{ex+d}}{\sqrt{ \left ( ae-bd \right ) b}}} \right ) }+2\,{\frac{{b}^{2}Ba}{ \left ( ae-bd \right ) ^{3}\sqrt{ \left ( ae-bd \right ) b}}\arctan \left ({\frac{b\sqrt{ex+d}}{\sqrt{ \left ( ae-bd \right ) b}}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Fricas [B] time = 1.45535, size = 1823, normalized size = 12.07 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Sympy [A] time = 30.9114, size = 136, normalized size = 0.9 \begin{align*} \frac{2 b \left (- A b + B a\right )}{\sqrt{d + e x} \left (a e - b d\right )^{3}} + \frac{2 b \left (- A b + B a\right ) \operatorname{atan}{\left (\frac{\sqrt{d + e x}}{\sqrt{\frac{a e - b d}{b}}} \right )}}{\sqrt{\frac{a e - b d}{b}} \left (a e - b d\right )^{3}} - \frac{2 \left (- A b + B a\right )}{3 \left (d + e x\right )^{\frac{3}{2}} \left (a e - b d\right )^{2}} + \frac{2 \left (- A e + B d\right )}{5 e \left (d + e x\right )^{\frac{5}{2}} \left (a e - b d\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Giac [B] time = 2.6588, size = 383, normalized size = 2.54 \begin{align*} -\frac{2 \,{\left (B a b^{2} - A b^{3}\right )} \arctan \left (\frac{\sqrt{x e + d} b}{\sqrt{-b^{2} d + a b e}}\right )}{{\left (b^{3} d^{3} - 3 \, a b^{2} d^{2} e + 3 \, a^{2} b d e^{2} - a^{3} e^{3}\right )} \sqrt{-b^{2} d + a b e}} - \frac{2 \,{\left (3 \, B b^{2} d^{3} + 15 \,{\left (x e + d\right )}^{2} B a b e - 15 \,{\left (x e + d\right )}^{2} A b^{2} e + 5 \,{\left (x e + d\right )} B a b d e - 5 \,{\left (x e + d\right )} A b^{2} d e - 6 \, B a b d^{2} e - 3 \, A b^{2} d^{2} e - 5 \,{\left (x e + d\right )} B a^{2} e^{2} + 5 \,{\left (x e + d\right )} A a b e^{2} + 3 \, B a^{2} d e^{2} + 6 \, A a b d e^{2} - 3 \, A a^{2} e^{3}\right )}}{15 \,{\left (b^{3} d^{3} e - 3 \, a b^{2} d^{2} e^{2} + 3 \, a^{2} b d e^{3} - a^{3} e^{4}\right )}{\left (x e + d\right )}^{\frac{5}{2}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]